In a circular coil (1) of radius $R$ , current $I$ is flowing and in another coil (2) of radius $2 R$ a current $2 I$ is flowing, then the ratio of the magnetic fields produced by the two coils is

1:1

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2:1

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1:2

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3:1

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Solution

The correct option is A 1:1
Magnetic field for coil 1
$b_{1} = \frac{μ_{0} N l}{2 R}$
Magnetic field for coil 2
$B_{2} = \frac{μ_{0} N (2 l)}{2 (2 R)} = \frac{μ_{0} N l}{2 R}$
$∴ \frac{B_{1}}{B_{2}} = \frac{1}{1}$

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In a circular coil (1) of radius R, current I is flowing and in another coil (2) of radius 2R a current 2I is flowing, then the ratio of the magnetic fields produced by the two coils is

The correct option is A 1:1Magnetic field for coil 1b1=μ0Nl2RMagnetic field for coil 2B2=μ0N(2l)2(2R)=μ0Nl2R∴B1B2=11

In a circular coil (1) of radius $R$ , current $I$ is flowing and in another coil (2) of radius $2 R$ a current $2 I$ is flowing, then the ratio of the magnetic fields produced by the two coils is

The correct option is A 1:1
Magnetic field for coil 1
$b_{1} = \frac{μ_{0} N l}{2 R}$
Magnetic field for coil 2
$B_{2} = \frac{μ_{0} N (2 l)}{2 (2 R)} = \frac{μ_{0} N l}{2 R}$
$∴ \frac{B_{1}}{B_{2}} = \frac{1}{1}$