Question

In a circus, a motorcyclist performs his stunts in a hollow sphere. Assume the thickness of the sphere to be negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform his stunts.(Take $\pi =\frac{22}{7}$)

• A. 516$m^2$
• B. 616$m^2$
• C. 586$m^2$
• D. 486$m^2$

Answer 1

The correct option is B

616$m^2$

Radius of the sphere,$r=\frac{\text{diameter of the sphere}}{2}=\frac{14m}{2}=7m$

Area available for the motorcyclist to perform stunts = Surface area of the sphere
$=4\pi r^2$
$=4\times \frac{22}{7}\times 7^2$
$=616m^2$