In a circus, a motorcyclist performs his stunts in a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is $14 m,$ then find the area available for the motorcyclist to perform stunts. $(Take π = \frac{22}{7})$

516m²

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616m²

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586m²

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486m²

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Solution

The correct option is B
616m²

Radius of the sphere $= \frac{diameter}{2} = 142 = 7 m$

Area available to the motorcyclist = Surface area of the sphere

$= 4 π r^{2}$

$= 4 \times \frac{22}{7} \times 7^{2}$

$= 616 m^{2}$

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In a circus, a motorcyclist performs his stunts in a hollow sphere. Assume the thickness of the sphere to be negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform his stunts.(Take $π = \frac{22}{7}$ )

In a circus, a motorcyclist performs his stunts inside a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform his stunts.
$(u s e π = \frac{22}{7})$

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In a circus, a motorcyclist performs his stunts in a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform stunts. (Take π=227)

The correct option is B 616m2 Radius of the sphere =diameter2=142=7 m Area available to the motorcyclist = Surface area of the sphere =4πr2 =4×227×72 =616 m2

In a circus, a motorcyclist performs his stunts in a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is $14 m,$ then find the area available for the motorcyclist to perform stunts. $(Take π = \frac{22}{7})$

The correct option is B
616m²

Radius of the sphere $= \frac{diameter}{2} = 142 = 7 m$

Area available to the motorcyclist = Surface area of the sphere

$= 4 π r^{2}$

$= 4 \times \frac{22}{7} \times 7^{2}$

$= 616 m^{2}$