In a circus, a motorcyclist performs his stunts in a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform stunts.(Take $π = \frac{22}{7}$ )

516m²

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616m²

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586m²

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486m²

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Solution

The correct option is B
616m²

Radius of the sphere $= \frac{d i a m e t e r}{2} = 142 = 7 m$

Area available to the motorcyclist= Surface area of the sphere

$= 4 π r^{2}$

$= 4 \times \frac{22}{7} \times 7^{2}$

$= 616 m^{2}$

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In a circus, a motorcyclist performs his stunts in a hollow sphere. Assume the thickness of the sphere to be negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform his stunts.(Take $π = \frac{22}{7}$ )

In a circus, a motorcyclist performs his stunts inside a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform his stunts.
$(u s e π = \frac{22}{7})$

Q. A hollow sphere in which a circus motorcyclist performs his stunts, has an inner diameter of

7 m

. Find the area available to the motorcyclist for riding. (Take

π = \frac{22}{7}

)

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7 m

. Find the area available to motorcyclist for riding.

In a circus, a motorcyclist performs his stunts in a death-well which is in the form of a hollow cylinder. The thickness of the cylinder is negligible. If the diameter of the hollow cylinder is 14 m, and height is 20 m, then find the area available for the motorcyclist to perform stunts. (Take $π = \frac{22}{7}$ )

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In a circus, a motorcyclist performs his stunts in a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform stunts.(Take π=227)

The correct option is B 616m2 Radius of the sphere =diameter2=142=7 m Area available to the motorcyclist= Surface area of the sphere =4πr2 =4×227×72 =616m2

In a circus, a motorcyclist performs his stunts in a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform stunts.(Take $π = \frac{22}{7}$ )

The correct option is B
616m²

Radius of the sphere $= \frac{d i a m e t e r}{2} = 142 = 7 m$

Area available to the motorcyclist= Surface area of the sphere

$= 4 π r^{2}$

$= 4 \times \frac{22}{7} \times 7^{2}$

$= 616 m^{2}$