In a circus, a motorcyclist performs stunts in a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is $14 m,$ then find the area available for the motorcyclist to perform stunts. [Take $π = \frac{22}{7}$ ]

516m²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

616m²

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

586m²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

486m²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
616m²

Radius of the sphere $= \frac{diameter}{2} = \frac{14}{2} = 7 m$

Area available to the motorcyclist $=$ Surface area of the sphere

$= 4 π r^{2}$

$= 4 \times \frac{22}{7} \times 7^{2}$

$= 616 m^{2}$

Suggest Corrections

Similar questions

In a circus, a motorcyclist performs his stunts inside a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform his stunts.
$(u s e π = \frac{22}{7})$

In a circus, a motorcyclist performs his stunts in a hollow sphere. Assume the thickness of the sphere to be negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform his stunts.(Take $π = \frac{22}{7}$ )

In a circus, a motorcyclist performs his stunts in a death-well which is in the form of a hollow cylinder. The thickness of the cylinder is negligible. If the diameter of the hollow cylinder is 14 m, and height is 20 m, then find the area available for the motorcyclist to perform stunts. (Take $π = \frac{22}{7}$ )

Q. A hollow sphere in which a circus motorcyclist performs his stunts, has an inner diameter of

7 m

. Find the area available to the motorcyclist for riding. (Take

π = \frac{22}{7}

)

Join BYJU'S Learning Program

In a circus, a motorcyclist performs stunts in a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform stunts. [Take π=227]

The correct option is B 616m2 Radius of the sphere =diameter2=142=7 m Area available to the motorcyclist = Surface area of the sphere =4πr2 =4×227×72 =616 m2

In a circus, a motorcyclist performs stunts in a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is $14 m,$ then find the area available for the motorcyclist to perform stunts. [Take $π = \frac{22}{7}$ ]

The correct option is B
616m²

Radius of the sphere $= \frac{diameter}{2} = \frac{14}{2} = 7 m$

Area available to the motorcyclist $=$ Surface area of the sphere

$= 4 π r^{2}$

$= 4 \times \frac{22}{7} \times 7^{2}$

$= 616 m^{2}$