In a circus, stuntman rides a motorbike in a circular track of radius R in the vertical plane. The minimum speed at highest point of track will be :

\sqrt{2 g R}

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2 g R

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\sqrt{3 g R}

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\sqrt{g R}

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Solution

The correct option is D $\sqrt{g R}$
let, velocity $=$ $V$ and the radius is $R$ .
At highest point
$m g + N = \frac{m V^{2}}{R}$
for $V_{m i n}, N = 0$ , $v_{m i n} = \sqrt{g r}$

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In a circus, stuntman rides a motorbike in a circular track of radius R in the vertical plane. The minimum speed at highest point of track will be :

The correct option is D √gRlet, velocity=V and the radius is R.At highest point mg+N=mV2Rfor Vmin,N=0 ,vmin=√gr

The correct option is D $\sqrt{g R}$
let, velocity $=$ $V$ and the radius is $R$ .
At highest point
$m g + N = \frac{m V^{2}}{R}$
for $V_{m i n}, N = 0$ , $v_{m i n} = \sqrt{g r}$