Question

In a cirucit, 5 percent of total current passes through a galvanometer. If resistance of the galvanometer is G. Then the value of the shunt is

• A. 19 G
• B. 20 G
• C. $\frac{G}{20}$
• D. $\frac{G}{19}$

Answer 1

Answer: (D)

$\frac{G}{19}$

Let the total passing be $I$.

Thus current passing through galvanometer $I_G=0.05I$

Also, current passing through shunt resistance $I_s=I-0.05I=0.95I$

Using $I_{s}S=I_{G}G$

$\therefore$ $\frac{S}{G}=\frac{0.05}{0.95}=\frac{1}{10}$

$⟹S=\frac{G}{19}$