In a city 20% of the population travels by car, 50% travels by bus and 10% travels by both car and bus. Then, persons travelling by car or bus is
(a) 80%
(b) 40%
(c) 60%
(d) 70%

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Solution

(c) 60%
Suppose C and B represents the population travel by car and Bus respectively.

$n (C \cup B) = n (C) + n (B) - n (B \cap C) = 0.20 + 0.50 - 0.10 = 0.6 o r 60 %$

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In a city 20% of the population travels by car, 50% travels by bus and 10% travels by both car and bus. Then, persons travelling by car or bus is (a) 80% (b) 40% (c) 60% (d) 70%

(c) 60% Suppose C and B represents the population travel by car and Bus respectively. nC∪B = nC + nB - nB∩C =0.20 + 0.50 - 0.10 =0.6 or 60%

In a city 20% of the population travels by car, 50% travels by bus and 10% travels by both car and bus. Then, persons travelling by car or bus is
(a) 80%
(b) 40%
(c) 60%
(d) 70%

(c) 60%
Suppose C and B represents the population travel by car and Bus respectively.

$n (C \cup B) = n (C) + n (B) - n (B \cap C) = 0.20 + 0.50 - 0.10 = 0.6 o r 60 %$