Let n(s)=100 and A be the event of selecting a member of eco club.
P(A)=40100=25
Let B be the event of selecting a member of mathematics club.
P(B)=25100=14
Since, A and B are mutually exclusive events
we have, P(A∪B)=P(A)+P(B)=25+14=1320
∴ the probability of selecting a student who is a member of eco club or mathematics club is 1320.
Now, the event C of selecting a student who is not a member of either of the clubs is the complementary event of (A∪B).
Thus, P(A∪B)+P(C)=1
P(C)=1−P(A∪B)=1−1320=720
∴ The probability of selecting a student who is not a member of either of the clubs is 720