In a class $A$ of $25$ students, $20$ passed with $60 %$ or more marks; in another class $B$ of $30$ students, $24$ passed with $60 %$ or more marks. In which class was a greater fraction of students getting with $60 %$ or more marks?

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Solution

Step $1 :$ Find the fraction of students in class $A$ who passed with $60 %$ or more marks.
Since, there are $25$ students in class $A$ . and $20$ students are passed with $60 %$ or more marks.
So, the required fraction is $\frac{20}{25} = \frac{4}{5}$ .
Hence, the fraction of students in class $A$ who passed with $60 %$ or more marks is $\frac{4}{5}$ .
Step $2 :$ Find the fraction of students in class $B$ who passed with $60 %$ or more marks.
Since, there are $30$ students in class $B$ . and $24$ students are passed with $60 %$ or more marks.
So, the required fraction is $\frac{24}{30} = \frac{4}{5}$ .
Hence, the fraction of students in class $B$ who passed with $60 %$ or more marks is $\frac{4}{5}$ .
Therefore, In both classes equal fraction of students passed with $60 %$ or more marks [ i.e., $\frac{4}{5}$ ].

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In a class A of 25 students, 20 passed with 60% or more marks; in another class B of 30 students, 24 passed with 60% or more marks. In which class was a greater fraction of students getting with 60% or more marks?

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