In a class, a teacher has given a quadratic equation $x^{2} - 3 x + 2 = 0$ to solve. A kid in the class replied that we can solve by writing coefficient of $x$ as a sum of the factors of constant. The teacher replied we can’t solve like that. Is the teacher’s reply true or false?

True

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False

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Solution

The correct option is A
True

The given equation is $x^{2} - 3 x + 2 = 0$

2 can be factorized into 2 and 1

i.e, 2 = 2 $\times$ 1

we can write 3 as 2 + 1

Therefore the given equation becomes x $^{2}$ - 2x - x + 2

$\Rightarrow$ x(x - 2) -1(x - 2) = 0

$\Rightarrow$ (x - 1)(x - 2) = 0

x = 1, 2

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In a class, a teacher has given a quadratic equation x2−3x+2=0 to solve. A kid in the class replied that we can solve by writing coefficient of x as a sum of the factors of constant. The teacher replied we can’t solve like that. Is the teacher’s reply true or false?

The correct option is A True The given equation is x2−3x+2=0 2 can be factorized into 2 and 1 i.e, 2 = 2 ×1 we can write 3 as 2 + 1 Therefore the given equation becomes x2 - 2x - x + 2 ⇒ x(x - 2) -1(x - 2) = 0 ⇒ (x - 1)(x - 2) = 0 x = 1, 2

In a class, a teacher has given a quadratic equation $x^{2} - 3 x + 2 = 0$ to solve. A kid in the class replied that we can solve by writing coefficient of $x$ as a sum of the factors of constant. The teacher replied we can’t solve like that. Is the teacher’s reply true or false?

The correct option is A
True

The given equation is $x^{2} - 3 x + 2 = 0$

2 can be factorized into 2 and 1

i.e, 2 = 2 $\times$ 1

we can write 3 as 2 + 1

Therefore the given equation becomes x $^{2}$ - 2x - x + 2

$\Rightarrow$ x(x - 2) -1(x - 2) = 0

$\Rightarrow$ (x - 1)(x - 2) = 0

x = 1, 2