In a class of 100 students, 55 students have passed in Mathematics and 67 students have passed in physics. Then the number of students who have passed in physics only is
A
22
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B
33
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C
10
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D
45
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Solution
The correct option is D45
The number of students passed in Mathematics, n(M)=55
The number of students passed in Physics, n(P)=67
Total number of students, n(M∪P)=100
Let no. of students passed in both subjects =n(P∩M)
n(M∪P)=n(M)+n(P)−n(P∩M)
100=55+67−n(P∩M)
n(P∩M)=122−100=22
No. of students passed in Physics but not in Maths, n(P∩M′)=n(P)−n(P∩M)