In a class of 180, where girls are twice the number of boys, Rupesh[a boy] ranked 34th from the top. If there are 18 girls ahead of Rupesh, how many boys are after him in rank?

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Solution

The correct option is B 44
No. of boys upto the 34th rank = 34-18 = 16
Total no of boys = $\frac{180}{2 + 1} \times = 60$
$∴$ number of boys after the rank of Rupesh = 60 - 16 = 44

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In a class of 180, where girls are twice the number of boys, Rupesh[a boy] ranked 34th from the top. If there are 18 girls ahead of Rupesh, how many boys are after him in rank?

The correct option is B 44No. of boys upto the 34th rank = 34-18 = 16Total no of boys =1802+1×=60∴ number of boys after the rank of Rupesh = 60 - 16 = 44

The correct option is B 44
No. of boys upto the 34th rank = 34-18 = 16
Total no of boys = $\frac{180}{2 + 1} \times = 60$
$∴$ number of boys after the rank of Rupesh = 60 - 16 = 44