You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Difference of Two Sets

In a class of...

Question

In a class of $30$ students, $10$ take mathematics, $15$ take physics and $10$ take neither. The number of students who take both mathematics and physics is

15

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $5$
$n (A \cup B) = n (A) + n (B) - n (A \cap B)$
$20 = 10 + 15 - n (A \cap B) o r n (A \cap B) = 5$

Suggest Corrections

Similar questions

Q. In a class, there are

200

students in which

120

take Mathematics,

90

take Physics,

60

take Chemistry,

50

take Mathematics and Physics,

50

take Mathematics and Chemistry,

43

take Physics and Chemistry and

38

take Mathematics, Physics and Chemistry. Then the number of students who have taken exactly one subject is

In a class of 40 students 14 take physics and 29 take chemistry. If 5 students take both, how many students take neither of the subjects?

Q. In a class of

70

students,

38

students like physics,

21

students like mathematics and

15

students like both the subjects, then the number of students who like neither of the subjects is

A group of 120 students, 90 take mathematics and 72 take economics. If 10 students take neither of the two, how many students take both:

In a class,110 students like physics, 80 like chemistry, 120 like mathematics and 70 like English. 20 students like only physics, 15 like only chemistry, 30 like only mathematics and 15 like only English. What can be the maximum possible number of students in the class ?

Join BYJU'S Learning Program

In a class of 30 students, 10 take mathematics, 15 take physics and 10 take neither. The number of students who take both mathematics and physics is

The correct option is B 5n(A∪B)=n(A)+n(B)−n(A∩B)20=10+15−n(A∩B)orn(A∩B)=5

In a class of $30$ students, $10$ take mathematics, $15$ take physics and $10$ take neither. The number of students who take both mathematics and physics is

The correct option is B $5$
$n (A \cup B) = n (A) + n (B) - n (A \cap B)$
$20 = 10 + 15 - n (A \cap B) o r n (A \cap B) = 5$