In a class of 30 students, 18 students play cricket, 15 students play football 12 play both the games. How many students in the class don't play both the games?

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Solution

$\cup = 30$ , $n (C) = 18$ , $n (F) = 15$ , $n (C \cap F) = 12$

Total no. of students who play football, cricket or both.

$\Rightarrow n (C \cup F) = n (C) + n (F) - n (C \cap F)$

$= 18 + 15 - 12$

$= 21$

$∴$ No. of students who does not play any game is

i.e., $n (C \cup F)^{^{'}} = n (\cup) - n (C \cup F)$

$= 30 - 21$

$= 9$

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In a class of 30 students, 18 students play cricket, 15 students play football 12 play both the games. How many students in the class don't play both the games? __

∪=30, n(C)=18, n(F)=15, n(C∩F)=12 Total no. of students who play football, cricket or both. ⇒n(C∪F)=n(C)+n(F)−n(C∩F) =18+15−12 =21 ∴ No. of students who does not play any game is i.e., n(C∪F)′=n(∪)−n(C∪F) =30−21 =9

In a class of 30 students, 18 students play cricket, 15 students play football 12 play both the games. How many students in the class don't play both the games?

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