Question

In a class of $50$ students, $\frac{1}{5}$ of the total play football, $\frac{3}{5}$ play cricket and the remaining play basketball. Find the number of students who play basketball, football, cricket

Answer 1

Given that,

In a class of $50$ students, $\frac{1}{5}$ of the total play football, $\frac{3}{5}$ play cricket, and the remaining play basketball.

Number of students who play football$=$$\frac{1}{5}$$\times$total number of students in a class

$=$$\frac{1}{5}$$\times$$50$

$=$$\frac{50}{5}$

$=$$10$

Number of students who play cricket$=$$\frac{3}{5}$$\times$total number of students in a class

$=$$\frac{3}{5}$$\times$$50$

$=$$\frac{3\times 50}{5}$

$$\begin{gathered} =\frac{150}{5} \\ =30 \end{gathered}$$

Number of students who play basketball$=$total number of students $-$ (number of students played football$+$number of students played cricket)

$$\begin{gathered} =50-\left(10+30\right) \\ =50-40 \\ =10 \end{gathered}$$

Therefore, the number of students who play basketball, football, and cricket is $10,10$ and $30$ respectively.