Question

In a class of 50 students, there are 18 girls and 32 boys. Of these students ,20 are vegetarians and rest non_vegetarians and 12 of the vegetarians are boys .if a students is chosen at random , what is probability of:(A) choosing a girl?,(B) choosing a non vegetarian student ? , (C) choosing a boy student who is non vegetarian? (D) choosing a girl who is vegetarian?.

Answer 1

$$\begin{gathered} \mathrm{There}\mathrm{are}18\mathrm{girls}\mathrm{and}32\mathrm{boys}\mathrm{and}\mathrm{in}\mathrm{total}50\mathrm{student}. \\ 20\mathrm{vegetarian}\mathrm{and}30\mathrm{non}\mathrm{vegetarian} \\ \mathrm{Out}\mathrm{of}20\mathrm{vegetarian}12\mathrm{are}\mathrm{boys}\mathrm{so}8\mathrm{are}\mathrm{girls}\mathrm{vegetarian}. \\ \mathrm{SO}\mathrm{there}\mathrm{are}32-12=20\mathrm{non}\mathrm{vegetarian}\mathrm{boys} \\ \mathrm{Now}\mathrm{probability}\mathrm{of}\mathrm{choosing}\mathrm{a}\mathrm{girl}=\frac{18}{50}=\frac{9}{25} \\ \mathrm{Choosing}\mathrm{a}\mathrm{non}\mathrm{vegetarian}\mathrm{student}=\frac{30}{50}=\frac{3}{5} \\ \mathrm{Choosing}\mathrm{a}\mathrm{boy}\mathrm{who}\mathrm{is}\mathrm{non}\mathrm{vegetarian}=\frac{20}{32}=\frac{5}{8} \\ \mathrm{Choosing}\mathrm{a}\mathrm{girl}\mathrm{who}\mathrm{is}\mathrm{vegetarian}=\frac{8}{18}=\frac{4}{9} \end{gathered}$$