Question

In a class of 51 students, where number of girls are twice that of number of boys, Kashyapi ranked 18^th from the top. If there are 6 girls ahead of Kashyapi, how many boys will be ranked after her?

• A. 11
• B. 7
• C. 6
• D. 27
• E. None of these

Answer 1

The correct option is C

6

Let the number of boys be x

Then, number of girls = 2x

$\therefore$x + 2x = 51 or 3x = 51 or x = 17

So, number of boys = 17 and number of girls = 34.

Number of students behind Kashyapi in rank (51 - 18) = 33.

Number of girls ahead of Kashyapi in rank = 6

Number of girls behind Kashyapi in rank = (34 - 6 -1) = 27

Number of boys behind Kashyapi in rank = (33 - 27) = 6