In a class of 60, where the number of girls is twice that of the boys, Kamal is ranked seventeenth from the top. If there are 9 girls ahead of Kamal then, how many boys are after him in rank?
A
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C12 Let the number of boys be x. Then, number of girls =2x. ∴x+2x=60 or 3x=60 or x=20 So, number of boys =20 and number of girls =40. Number of students behind Kamal in rank (60−17)=43. Number of girls ahead of Kamal in rank =9 Number of girls behind Kamal in rank =(40−9)=31 ∴ Number of boys behind Kamal in rank =(43−31)=12.