In a class of 80 students it is found that 40 students like Tajmahal and 50 students like Charminar and 18 like both. Then the number of students who do not like neither are.

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Solution

The correct option is B 8
Given that
Total students $= 80$
Students who like Tajmahal $= 40 n (T)$
Students who like charminar $= 50 n (C)$
Students who like both $= 18 n (T \cap C)$
Say $^{'} x^{'}$ like neither then,
$80 = n (T) + n (C) - n (T \cap C) + x \Rightarrow 80 = 40 + 50 - 18 + x \Rightarrow x = 8$

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In a class of 80 students it is found that 40 students like Tajmahal and 50 students like Charminar and 18 like both. Then the number of students who do not like neither are.

The correct option is B 8Given thatTotal students=80Students who like Tajmahal =40n(T)Students who like charminar=50n(C)Students who like both =18n(T∩C)Say ′x′ like neither then,80=n(T)+n(C)−n(T∩C)+x⇒80=40+50−18+x⇒x=8