Question

In a class, there are 14 boys and 11 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:

• A. 21/46
• B. 10/11
• C. 7/8
• D. 21/23
• E. none

Answer 1

The correct option is E

none

Let S be the sample space and E be the event of selecting 1 girl and 2 boys.

Then, (S) = Number ways of selecting 3 students out of 25

${}^{25}{C}_3$ =2300

n(E) = (${}^{11}{C}_1{\times }^{14}{C}_2$)= 1001

P(E) = $\frac{1001}{2300}$.