In a class, there are 30 badminton players and 40 cricket players. The total strength of the class is 50. Find the number of players who play only badminton (assume every student plays at least one of the games).
10
In the given question, n (U) = 50, n (A) = 30, n (B) = 40 where set A is of badminton players and set B is of cricket players.
Now, number of players play both badminton and cricket i.e., n (A ∩ B) = n (A) + n (B) - n (A U B)
= 30 + 40 - 50
= 20
Therefore, number of students play only badminton = n (A) - n ( A ∩ B)
= 30 - 20
= 10