In a close pack array of $N$ spheres, the number of tetrahedral holes are:

8 N

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N / 2

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2 N

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4 N

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Solution

The correct option is C $2 N$
In a cubic closed packing arrangement of spheres, the number of tetrahedral holes is twice the number of atoms that make up the packing arrangement, and also twice the number of octahedral voids. Hence, if there are N spheres in the arrangement, there would be $2 N$ tetrahedral voids.
Thus, (C) is correct answer.

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In a close pack array of N spheres, the number of tetrahedral holes are:

In a close pack array of $N$ spheres, the number of tetrahedral holes are: