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Question

In a close vessel 4 L CH4 gas is present at 60 mm Hg pressure. If 1 litre of water is filled into the container, then find the total pressure of gas mixture (Assuming vapour pressure of water at that temperature = 20 mm Hg)

A
100 mm Hg
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B
106.7 mm Hg
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C
80 mm Hg
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D
40 mm Hg
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Solution

The correct option is A 100 mm Hg
According to Boyle's law
P1V1=P2V2
60×4=P2×3
P2=80 mm Hg
Given, PH2O=20 mm Hg
Therefore, total pressure, PT=(80+20) mm Hg=100 mm Hg

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