In a closed container and at constant temperature 0.3 mole of SO2 and 0.2 mole of O2gas at 750 torr are kept with a catalyst. If at equilibrium 0.2 mole of SO3 is formed the partial pressure of SO2 in torr :
A
375
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B
187
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C
360
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D
150
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Solution
The correct option is B187
SO2+12O2⇋SO3
0.3 0.2 0 ------- initial
0.3-0.2 0.2-0.1 0.2 ---- --- final
=0.1 =0.1
Mole fraction of a component=moles of that componenttotal number of moles
Mole fraction of SO2=0.10.1+0.1+0.2=0.10.4=0.25
Partial pressure of SO2=mole fraction of SO2×total pressure