wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a closed container and at constant temperature 0.3 mole of SO2 and 0.2 mole of O2 gas at 750 torr are kept with a catalyst. If at equilibrium 0.2 mole of SO3 is formed the partial pressure of SO2 in torr :

A
375
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
187
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
360
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
150
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 187
SO2+12O2SO3
0.3 0.2 0 ------- initial
0.3-0.2 0.2-0.1 0.2 ---- --- final
=0.1 =0.1

Mole fraction of a component=moles of that componenttotal number of moles

Mole fraction of SO2=0.10.1+0.1+0.2=0.10.4=0.25

Partial pressure of SO2=mole fraction of SO2×total pressure

Partial pressure of SO2=0.25×750 torr=187 torr

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reactions in Solutions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon