In a closed container at a given temperature, pressure increases from 100 mm Hg to 160 mm Hg in 10 sec. for reaction.
Then the average rate of reaction in first 10 sec. will be?

2 mm/sec.

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4 mm/sec.

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6 mm/sec.

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3 mm/sec.

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Solution

The correct option is A 6 mm/sec.
$P_{1} = 100 m m H g$
$P_{2} = 160 m m H g$
time period $= 10 s e c$
average rate of reaction $= \frac{160 - 100}{10 - 0}$
$= 6 m m / s e c$

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