Question

In a closed cylinder there are $60\text{g}Ne$ and $64\text{g}{O}_2$. If pressure of mixture of gases in cylinder is 30 bar, then partial pressure of $O_2$ in this cylinder will be (in bar).

Answer 1

As partial pressure $\propto$ number of moles
so $\frac{P_{O_2}}{P_{O_2}+P_{Ne}}=\frac{n_{O_2}}{n_{O_2}+n_{Ne}}$
where ${\mu }_{O_2}=\frac{64}{32}=2$ and ${\mu }_{Ne}=\frac{60}{20}=3$
$\Rightarrow \frac{P_{O_2}}{30\text{bar}}=\frac{2}{2+3}\Rightarrow P_{O_2}=12\text{bar}$