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Standard XII

Physics

Tension

In a closed e...

Question

In a closed end organ pipe, if $l_{1}$ and $l_{2}$ are two successive resonating lengths, then $2 (l_{2} - l_{1})$ is ________ .

\frac{λ}{2}

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λ

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2 λ

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None of these

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Solution

The correct option is B $λ$
In close- end organ pipe the resonance length is given by:
$l = \frac{(2 n - 1) λ}{4}$ , where $n = 1, 2, 3..$
So, $l_{1} = \frac{(2 n - 1) λ}{4}$ and
$l_{2} = \frac{(2 (n + 1) - 1) λ}{4}$
or, $(l_{2} - l_{1}) = λ / 2$
or, $2 (l_{2} - l_{1}) = λ$ .

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In a closed end organ pipe, if l1 and l2 are two successive resonating lengths, then 2(l2−l1) is ________ .

The correct option is B λIn close- end organ pipe the resonance length is given by:l=(2n−1)λ4, where n=1,2,3..So, l1=(2n−1)λ4 andl2=(2(n+1)−1)λ4or, (l2−l1)=λ/2or,2(l2−l1)=λ.

In a closed end organ pipe, if $l_{1}$ and $l_{2}$ are two successive resonating lengths, then $2 (l_{2} - l_{1})$ is ________ .

The correct option is B $λ$
In close- end organ pipe the resonance length is given by:
$l = \frac{(2 n - 1) λ}{4}$ , where $n = 1, 2, 3..$
So, $l_{1} = \frac{(2 n - 1) λ}{4}$ and
$l_{2} = \frac{(2 (n + 1) - 1) λ}{4}$
or, $(l_{2} - l_{1}) = λ / 2$
or, $2 (l_{2} - l_{1}) = λ$ .