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Question

In a closed vessel, 5 moles of A2(g) and 7 moles B2 (g) are reacted in the following manner:


A2 (g) + 3B2 (g) 2AB3 (g)

What is the total number of moles of gases present in the container at the end of the reaction?

A
22/3
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B
7/3
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C
14/3
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D
8/3
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Solution

The correct option is A 22/3
A2 + 3B2 2AB3
5 moles 7 moles
Given: 5 moles of A2 and 7 moles of B2.

So, it means the B2 is limiting reagent.

Total number of moles of gases present in the container at the end of the reaction =143 moles of AB3 + (573) moles of A2 + (77) moles of B2=223.

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