Question

In a closed vessel, an ideal gas at $1atm$ is heated from ${27}^{\circ }C$ to ${327}^{\circ }C$. The final pressure of the gas will approximately be :

• A. $3atm$
• B. $0.5atm$
• C. $2atm$
• D. $12atm$

Answer 1

The correct option is C $2atm$

For an ideal gas we have :

$PV=nRT$

And at constant volume: $P\propto T$

Using the relation we get :

$\frac{P_1}{P_2}=\frac{T_1}{T_2}$

Given :

$P_1=1atm$

$T_1=27+273=300K$

$P_2=xatm$

$T_2=327+273=600K$

$\frac{1}{P_2}=\frac{300}{600}$

$\Rightarrow P_2=2$

Therefore the final pressure is 2 atm.

Option C is correct.