In a coil of area $10$ $c m^{2}$ and $10$ turns with magnetic field directed perpendicular to the plane and is changing at the rate of $10^{4}$ gauss/ second. The resistance of the coil is $20$ $Ω$ . The current in the coil will be

0.5 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

50 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 \times 10^{8} A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $5 A$
Induced current in the coil will be
$i = \frac{e m f}{R} = \frac{d B}{d t} \times \frac{A \times n}{R}$
$= \frac{10^{4}}{10^{4}} \times \frac{10 \times 10}{20}$
$= 5$ $A .$

Suggest Corrections

Similar questions

Q. A coil of area 10

{c m}^{2}

and 10 turns is in magnetic field directed perpendicular to the plane and changing at a rate of

10^{8}

gauss /s The resistance of coil is 20

Ω

. The current in the coil will be

Q. More than One Answer Type
एक से अधिक उत्तर प्रकार के प्रश्न

A coil of area 20 cm² and 100 turns is kept in a magnetic field, directed perpendicular to the plane. The magnetic field is changing at the rate of 10⁶ gauss/second. If resistance of the coil is 10 Ω, then

20 cm² क्षेत्रफल तथा 100 घेरों वाली एक कुण्डली को तल के लम्बवत् निर्देशित चुम्बकीय क्षेत्र में रखा जाता है। चुम्बकीय क्षेत्र 10⁶ गाऊस/सेकण्ड की दर से परिवर्तित हो रहा है। यदि कुण्डली का प्रतिरोध 10 Ω है, तब

A rectangular coil of $20$ turns and area of cross section $25 s q . c m$ has a resistance of $100 o h m$ . If a magnetic field which is perpendicular to the plane of the coil changes at a rate of $1000 t e s l a p e r s e c$ , the current in the coil is:

Q. A coil of area 5

c m^{2}

with

20

turns is kept under the magnetic field of

10^{3}

Gauss. Normal to the plane of coil makes an angle

30^{o}

with the magnetic field. The flux through the coil is

Q. A coil of 1200 turns and mean area of 500

c m^{2}

is held perpendicular to a uniform magnetic field of induction

4 \times 10^{- 4}

T. The resistance of the coil is 20 ohms. When the coil is rotated through

180^{0}

in the magnetic field in 0.1 s, the average electric current (in mA) induced is :

Join BYJU'S Learning Program

In a coil of area 10 cm2 and 10 turns with magnetic field directed perpendicular to the plane and is changing at the rate of 104 gauss/ second. The resistance of the coil is 20 Ω . The current in the coil will be

The correct option is A 5AInduced current in the coil will be i=emfR=dBdt×A×nR =104104×10×1020 =5 A.

In a coil of area $10$ $c m^{2}$ and $10$ turns with magnetic field directed perpendicular to the plane and is changing at the rate of $10^{4}$ gauss/ second. The resistance of the coil is $20$ $Ω$ . The current in the coil will be

The correct option is A $5 A$
Induced current in the coil will be
$i = \frac{e m f}{R} = \frac{d B}{d t} \times \frac{A \times n}{R}$
$= \frac{10^{4}}{10^{4}} \times \frac{10 \times 10}{20}$
$= 5$ $A .$