Question

In a cold climate, water gets frozen causing damage to radiator of a car. Ethylene glycol is used as antifreezing agent. Calculate the amount of ethylene glycol to be added to 4 kg of water to prevent it from freezing at $-6^{o}C(K_f$ for water =1.85 K kg $mo{l}^{-1}$

Answer 1

Given,
$△T=6^{o}C,W=4kg=4000g,m=62,K_f=1.85$
$w=\frac{m\times W\times △T}{1000\times K_f}$
$=\frac{62\times 4000\times 6}{1000\times 1.85}=804.32g$