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Question
In a collection of H−atoms, all the electrons jump from n=5 to ground level finally (directly or indirectly), without emitting any line in Balmer series. The number of possible different radiations is:
In a collection of H−atoms, all the electrons jump from n=5 to ground level finally (directly or indirectly), without emitting any line in Balmer series. The number of possible different radiations is:
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Solution
The correct option is D 6
Total number of lines = (n2−n1)(n2−n1+1)2=(5−4)(5−4+1)2= 10
Possible Balmer lines are = 5→2, 4→2,3→2
Since there are no Balmer lines observed, the transition 2→1 is also not possible.
Therefore, total number of possible different radiation = 10 - 4 = 6
Total number of lines = (n2−n1)(n2−n1+1)2=(5−4)(5−4+1)2= 10
Possible Balmer lines are = 5→2, 4→2,3→2
Since there are no Balmer lines observed, the transition 2→1 is also not possible.
Therefore, total number of possible different radiation = 10 - 4 = 6
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