In a college, $25 %$ of the boys and $10 %$ of the girls offer Mathematics. The girls constitute $60 %$ of the total number of student. If a student is selected at random and is found to be studying Mathematics, the probability that the student is a girl, is

\frac{1}{6}

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\frac{3}{8}

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\frac{5}{8}

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\frac{5}{6}

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Solution

The correct option is B $\frac{3}{8}$
Let 100 students studying in which 60 % girls and 40 % boys.
Boys = 40, Girls = 60
25% of boys offer Maths = (25/100)40=10 Boys
10% of girls offer Maths =(10/100)60=6Girls
It means, 16 students offer Maths.
Required probability=6/16=3/8

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In a college, 25% of the boys and 10% of the girls offer Mathematics. The girls constitute 60% of the total number of student. If a student is selected at random and is found to be studying Mathematics, the probability that the student is a girl, is

The correct option is B 38 Let 100 students studying in which 60 % girls and 40 % boys. Boys = 40, Girls = 60 25% of boys offer Maths = (25/100)*40=10 Boys 10% of girls offer Maths =(10/100)*60=6Girls It means, 16 students offer Maths. Required probability=6/16=3/8

In a college, $25 %$ of the boys and $10 %$ of the girls offer Mathematics. The girls constitute $60 %$ of the total number of student. If a student is selected at random and is found to be studying Mathematics, the probability that the student is a girl, is

The correct option is B $\frac{3}{8}$
Let 100 students studying in which 60 % girls and 40 % boys.
Boys = 40, Girls = 60
25% of boys offer Maths = (25/100)40=10 Boys
10% of girls offer Maths =(10/100)60=6Girls
It means, 16 students offer Maths.
Required probability=6/16=3/8