In a college, there are 10 periods per day each of 40 minutes. Students were shouting to reduce the number of periods but the Principal doesn't want to reduce the working hour. How will you help the Principal to reduce the number of periods to 8 without changing the total working hours?

30 minutes

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55 minutes

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50 minutes

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45 minutes

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Solution

The correct option is C
50 minutes

When number of periods is 10, time for each period is 40 mins.
Let the time for each period be y mins when number of periods is changed to 8.
$10 \times 40 = 8 \times y$
$\Rightarrow y = \frac{10 \times 40}{8} = 50 m i n u t e s$ .

The Principal should make each period of 50 mins.

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In a college, there are 10 periods per day each of 40 minutes. Students were shouting to reduce the number of periods but the Principal doesn't want to reduce the working hour. How will you help the Principal to reduce the number of periods to 8 without changing the total working hours?

The correct option is C 50 minutes When number of periods is 10, time for each period is 40 mins. Let the time for each period be y mins when number of periods is changed to 8. 10×40=8×y ⇒y=10×408=50 minutes. The Principal should make each period of 50 mins.