In a college there are 10 periods per day each of 40minutes. Students were shouting to reduce the number of periods but the principal doesn't want to reduce the working hour. How will you help the principal to reduce the number of periods to 8 without changing the total working hours?

30 minutes

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55 minutes

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50 minutes

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45 minutes

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Solution

The correct option is C
50 minutes

$\begin{matrix} N u m b e r o f p e r i o d s & 10 & 8 T i m e f o r e a c h p e r i o d (I n m i n u t e s) & 40 & y \end{matrix}$
10 × 40 = 8 × y ↔ y = $\frac{10 \times 40}{8}$ = 50 minutes.

Make periods each of 50 minutes.

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In a college there are 10 periods per day each of 40minutes. Students were shouting to reduce the number of periods but the principal doesn't want to reduce the working hour. How will you help the principal to reduce the number of periods to 8 without changing the total working hours?

The correct option is C 50 minutes Number of periods108Time for each period(In minutes)40y 10 × 40 = 8 × y ↔ y = 10×408 = 50 minutes. Make periods each of 50 minutes.

The correct option is C
50 minutes

$\begin{matrix} N u m b e r o f p e r i o d s & 10 & 8 T i m e f o r e a c h p e r i o d (I n m i n u t e s) & 40 & y \end{matrix}$
10 × 40 = 8 × y ↔ y = $\frac{10 \times 40}{8}$ = 50 minutes.

Make periods each of 50 minutes.