In a college, there are 20 students who enrolled for commerce only,90 students enrolled for mathematics only, 30 students enrolled for commerce and mathematics both and 60 students enrolled for others. Find the total number of students enrolled either in commerce or mathematics.

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120

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140

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Solution

The correct option is D 140
Given in the Venn diagram,

Let total number of students as U

Students of Commerce as B

Students of Mathematics as A

B – A = 20 A – B = 90 A∩B = 30

n(A∪B) = n(A-B) + n(A∩B) + n(B-A) that is, the formula of difference of sets
= 90 + 30 + 20

= 140

Hence there are 140 students who enrolled either for commerce or mathematics.

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