In a collision between two solid spheres. velocity of separation along the line of impact (assume no external forces act on the system of two spheres during impact):

Cannot be greater than velocity of approach

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Cannot be less than velocity of approach

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Cannot be equal to velocity of approach

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none of these

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Solution

The correct option is A Cannot be greater than velocity of approach
$\begin{matrix} e = \frac{v o l u m e o f s e p}{v o l u m e o f a p p} 0 < e < 1 \Rightarrow V o l u m e o f s e p < v o l u m e o f a p p \end{matrix}$
$∴$ Option $A$ is correct.

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In a collision between two solid spheres. velocity of separation along the line of impact (assume no external forces act on the system of two spheres during impact):

The correct option is A Cannot be greater than velocity of approache=volumeofsepvolumeofapp0<e<1⇒Volumeofsep<volumeofapp∴ Option A is correct.

The correct option is A Cannot be greater than velocity of approach
$\begin{matrix} e = \frac{v o l u m e o f s e p}{v o l u m e o f a p p} 0 < e < 1 \Rightarrow V o l u m e o f s e p < v o l u m e o f a p p \end{matrix}$
$∴$ Option $A$ is correct.