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Question

In a combined test in English and Physics; 36% candidates failed in English; 28% failed in Physics and 12% in both; find the percentage of passed candidates.

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Solution

Total percentage of candidates which failed can be found using the formula of union of sets
n(AUB)=n(A)+n(B)n(C)
So, n(AUB)=36+2812=52
Since 52 % of the total candidates failed , percentage of passed candidates =10052=48 %

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