In a combined test in English and Physics; 36% candidates failed in English; 28% failed in Physics and 12% in both; find the percentage of passed candidates.
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Solution
Total percentage of candidates which failed can be found using the formula of union of sets n(AUB)=n(A)+n(B)−n(C) So, n(AUB)=36+28−12=52 Since 52 % of the total candidates failed , percentage of passed candidates =100−52=48 %