Question

In a combined test in Maths and Chemistry; 84% candidates passed in Maths; 76% in Chemistry and 8% failed in both. Find : (i) the percentage of failed candidates. (ii) if 340 candidates passed in the test; then how many appeared ?

Answer 1

Since, candidates passed in Maths = 84%
$\because$ candidates failed in Maths = 100% - 84%
= 16%
Again, candidates passed in Chemistry = 76%
$\therefore$ Candidates failed in Chemistry = 100%- 76%
=24%
Candidates failed in both = 8%
$\therefore$ Candidates failed in only Maths
= 16% - 8% = 8%
Candidates failed in Chemistry
= 24% - 8% = 16%
Total failed candidates = 8% + 16% +8%
= 32%
(i) Percentage of failed candidates = 32%
(ii)Passed candidates = 100% - 32% = 68%
If passed candidate is 1 then total candidates appeared = $\frac{100}{68}$
If passed candidates are 340 total candidates appeared = $\frac{100}{68}\times 340$
= $\frac{100\times 340}{68}=500$