In a committee 50 people speak French, 20 speak Spanish and 10 speak both Spanish and French. The number of persons speaking at least one of these two languages is

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Solution

The correct option is A
60

$n (S \cup F)$ = $n (S) + n (F) - n (S \cap F)$

$\Rightarrow n (S \cup F)$ = 20 + 50 -10 = 60

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In a committee 50 people speak French, 20 speak Spanish and 10 speak both Spanish and French. The number of persons speaking at least one of these two languages is

The correct option is A 60 n(S∪F) = n(S)+n(F)−n(S∩F) ⇒n(S∪F) = 20 + 50 -10 = 60

The correct option is A
60

$n (S \cup F)$ = $n (S) + n (F) - n (S \cap F)$

$\Rightarrow n (S \cup F)$ = 20 + 50 -10 = 60