Question

In a common-base mode of a transistor, the collector current is $5.488\text{mA}$ for an emitter current of $5.60\text{mA}$. The value of the current amplification factor $\left(\beta \right)$ will be

• A. $49$
• B. $50$
• C. $51$
• D. $48$

Answer 1

The correct option is A $49$

Given
$I_C=5.488\text{mA}$
$I_E=5.60\text{mA}$

According to KCL,
$I_E=I_C+I_B$
$\Rightarrow 5.6=5.488+I_B$
$\Rightarrow I_B=0.112\text{mA}$

Now, the current amplification factor is,
$\beta =\frac{I_C}{I_B}=\frac{5.488}{0.112}=49$

Hence, $\left(A\right)$ is the correct answer.