In a common - emitter amplifier- output resistance is 5000 - and input resitance is 2000 - If peak value of signal voltage is 10 mV and -50- then the peak value of output voltage isA- 1-25 VB- 5 - 10-6 VC- 125 VD- 2-5 - 10-4 V

The correct option is A 1.25 VVoltage amplification (A_v)is A_v = βR_0R_i = 50 ×50002000 A_v=V_0V_max V_0/10 × 10^ 3 = 125 (∵ V_max=10 × 10^ 3 ) Output Vol ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

P-N Junction

In a common -...

Question

In a common - emitter amplifier, output resistance is $5000 Ω$ and input resitance is $2000 Ω$ . If peak value of signal voltage is $10 m V$ and $β = 50,$ then the peak value of output voltage is

5 \times 10^{- 6} V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.5 \times 10^{- 4} V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.25 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

125 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $1.25 V$
Voltage amplification $(A_{v})$ is
$A_{v} = - β \frac{R_{0}}{R_{i}}$
$= - 50 \times \frac{5000}{2000}$

$A_{v} = \frac{V_{0}}{V_{m a x}}$
$\frac{V_{0}}{10 \times 10^{- 3}} = - 125$ $(∵ V_{m a x} = 10 \times 10^{- 3})$
Output Voltage $V_{0} = - 1.25 V$

Suggest Corrections

Similar questions

Q. In a common-emitter amplifier, using output resistance of

5000 ohm

and input resistance of

2000 ohm

, if the peak value of input signal voltage is

10 mV

and

β = 50

, then the power gain is

Q. In a common-emitter amplifier, using output resistance of

5000 ohm

and input resistance of

2000 ohm

, if the peak value of input signal voltage is

10 mV

and

β = 50

, then the power gain is

Q. A

PNP

in common emitter configuration used as an amplifier, its current gain is

50

. If input resistance is

1 k Ω

and input voltage is

5 V

, then output current will be-

Q. A transistor has a current amplification factor (current gain) of

50

. In a common emitter amplifier circuit, the collector resistance is chosen as

5

Ω

and the input resistance is

1

Ω

. The output voltage if input voltage is

0.01

V

Q. In common emitter amplifier, the current gain is

62

.The collector resistance and input resistance are

5 k

Ω

500

Ω

respectively. If the input voltage is

0.01 V

, the output voltage is

Join BYJU'S Learning Program

In a common - emitter amplifier, output resistance is 5000 Ω and input resitance is 2000 Ω. If peak value of signal voltage is 10 mV and β=50, then the peak value of output voltage is

The correct option is C 1.25 VVoltage amplification (Av)is Av=−βR0Ri =−50×50002000 Av=V0Vmax V010×10−3=−125 (∵Vmax=10×10−3) Output Voltage V0=−1.25V

In a common - emitter amplifier, output resistance is $5000 Ω$ and input resitance is $2000 Ω$ . If peak value of signal voltage is $10 m V$ and $β = 50,$ then the peak value of output voltage is

The correct option is C $1.25 V$
Voltage amplification $(A_{v})$ is
$A_{v} = - β \frac{R_{0}}{R_{i}}$
$= - 50 \times \frac{5000}{2000}$

$A_{v} = \frac{V_{0}}{V_{m a x}}$
$\frac{V_{0}}{10 \times 10^{- 3}} = - 125$ $(∵ V_{m a x} = 10 \times 10^{- 3})$
Output Voltage $V_{0} = - 1.25 V$