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Byju's Answer
Standard XIII
Physics
Transistor: Working
In a common e...
Question
In a common emitter transistor circuit, the base current is
40
μ
A
, then
V
B
E
is :-
A
2
V
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B
0.2
V
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C
0.8
V
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D
Zero
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Solution
The correct option is
B
0.2
V
Given that
I
B
=
40
μ
A
Apply KVL
10
V
=
(
245
k
Ω
)
(
40
μ
A
)
+
V
B
E
V
B
E
=
(
10
−
9.8
)
V
=
0.2
V
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0
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