Question

In a common emitter transistor the current gain is 80. What is change in collector current, when change in base current is $250\mu A$

• A. $9\times {10}^{-2}A$
• B. $8\times {10}^{-6}A$
• C. $2\times {10}^{-2}A$
• D. $3\times {10}^{-7}A$

Answer 1

The correct option is C $2\times {10}^{-2}A$

$\begin{array}{c}Currentgiven=\beta =\frac{\Delta i_e}{\Delta i_b}\\ \Rightarrow \Delta i_e=\beta \times \Delta i_b\\ =80\times 20\mu A\\ =2\times {10}^{-2}A\end{array}$

Hence,

option $\left(C\right)$ is correct answer.