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Question

In a compound microscope the focal length of objective lens is 1.2 cm and focal length of eye piece is 3.0 cm. When object is kept at 1.25 cm in from of objective, final image is formed at infinity. Magnifying power of the compound microscope should be :

A
400
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B
200
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C
150
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D
100
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Solution

The correct option is A 200
Given fe=3cm and
fo=1.2cm
uo=1.25cm
ve=

From , 1uo+1vo=1fo,

we get 1vo=11.211.25

vo=30 cm

Magnification of microscope m=vouo(Dfe)

m=301.25(253)=200 .

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