In a compound microscope, the focal lengths of two lenses are 1.5 cm and 6.25 cm an object is placed at 2 cm form objective and the final image is formed at 25 cm from eye lens. The distance between the two lenses is
A
6.00 cm
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B
7.75 cm
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C
9.25 cm
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D
11.00 cm
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Solution
The correct option is D 11.00 cm It is given that f0=1.5cm,fe=6.25cm,u0=2cm When final image is formed at least distance of distinct vision, length of the tube LD=u0f0u0−f0+feDfe+D ⇒LD=2×1.52−1.5+6.25×256.25+25=11cm.