In a compound, nitrogen atoms (N) make cubic close packed lattice and metal atoms (M) occupy one-third of the tetrahedral voids present. Determine the formula of the compound formed by M and N?

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Solution

In ccp, no. of atoms per unit cell = 4 Thus, of tetrahedral voids = 2 x No. of atoms in ccp =2 x 4=8 Only one-third of tetrahedral voids are occupied by metal M. No. of M2N3

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