Question

In a compound of Xe, F and O
Xe = 60.4% (131.3)
F = 17.5% (19.0)
Thus, number of oxygen atoms is 3
if true enter 1, else enter 0.

• A. 1

Answer 1

The correct option is A 1
Assume the mass of sample is 100 g.
It will contain 60.4 g Xe, 17.5 g F and $100-(60.4+17.5)=22.1$ g Oxygen.
First calculate the number of moles of Xe present in 100 g of sample.
$\frac{60.4}{131.3}=0.46$ mol
Now calculate the number of moles of oxygen present in 100 g of sample.
$\frac{22.1}{16}=1.38$ mol
Now calculate the mole ratio of oxygen to xenon.
$\frac{1.38}{0.46}=3:1$.
Thus, the number of oxygen atoms present in the compound are 3.