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Question

In a concave mirror, an object is placed at a distance $$d
_1$$ from the focus and the image is formed at a distance $$d_2$$ from the focus. Then the focal length of the mirror is:


A
d1d2
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B
d1d2
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C
(d1+d2)/2
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D
d1/d2
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Solution

The correct option is C $$\sqrt{d_1d_2}$$
Let $$f$$ be the magnitude of the focal length of the mirror.

Using mirror equation ,

$$\dfrac{1}{v}+\dfrac{1}{u}=-\dfrac{1}{f}$$

$$\implies \dfrac{1}{-(d_1+f)}+\dfrac{1}{-(d_2+f)}=-\dfrac{1}{f}$$

$$\implies f=\sqrt{d_1d_2}$$

Physics

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